441=3x^2

Solution for 441=3x^2 equation:

441=3x^2

We move all terms to the left:

441-(3x^2)=0

a = -3; b = 0; c = +441;
Δ = b2-4ac
Δ = 02-4·(-3)·441
Δ = 5292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5292}=\sqrt{1764*3}=\sqrt{1764}*\sqrt{3}=42\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42\sqrt{3}}{2*-3}=\frac{0-42\sqrt{3}}{-6}
=-\frac{42\sqrt{3}}{-6}
=-\frac{7\sqrt{3}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42\sqrt{3}}{2*-3}=\frac{0+42\sqrt{3}}{-6}
=\frac{42\sqrt{3}}{-6}
=\frac{7\sqrt{3}}{-1}
$